Answer:
it from the planet is 4.51 unit
Explanation:
given data
time t1 = 7 days
distance a1= 5.0 units
time t2 = 6 days
to find out
How far is it from the planet
solution
we know that from Kepler second law of planetary motion
T² is directly proportional to a³
so T² = K a³ ...........1
here for for both time we can say
[tex]\frac{T1^2}{T2^2}= \frac{K a1^3}{K a2^3}[/tex]
a2³ = a1³ × [tex]\frac{T2^2}{T1^2}[/tex]
a2³ = 5³ × [tex]\frac{6^2}{7^2}[/tex]
a2³ = 4.51 unit
so it from the planet is 4.51 unit
