x-2y=0 ,x²+xy+y²=27

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m0m02004roma m0m02004roma

01-02-2020
Mathematics

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x-2y=0 ,x²+xy+y²=27

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jturner10659 jturner10659 · Answer 1 · 2020-02-02T00:10:04+01:00

Hello there i hope you are having a good day :) Your question : x-2y=0 ,x²+xy+y²=27 ? Answer : Firstly you would find the variable in one of the equations, then Takeaway the result into the other equation. So this would be

(1 - √ 433 /4) - (1 - √433/8) Then X would be (1 - √ 433 /4) and Y would be (1 - √433/8) Then you would add them (1 + √433/4) and (1 + √433/8) Same as before as X and .

Hopefully that helps ya ❤

x-2y=0 ,x²+xy+y²=27​

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x-2y=0 ,x²+xy+y²=27