ddira35 ddira35

02-02-2020
Mathematics

contestada

[tex]4(x - 1) {}^{2} - 9[/tex]

Respuesta :

LocalAskingMaster LocalAskingMaster

02-02-2020

Step-by-step explanation:

(a-b)^2=(a^2-2*a*b+b^2)

4*(x^2-2x+1)-9=4x^2-8x+4-9=4x^2-8x-5

if you have to calculate the Δ

there is it: 4x^2-8x-5=0

Δ=b^2-4*a*c=64-4*4*(-5)=64+80=144

[tex]x_{1,2}=[/tex]-b±Δ/2*a=8±12/8=

[tex]x_{1}[/tex]=8+12/8=20/8|:4=5/2

[tex]x_{2}[/tex]=8-12/8=-4/8|:4=-1/2

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