(1.33)sin 25.0= (1.50)sin 0 0=?

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02-09-2016
Physics

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(1.33)sin 25.0= (1.50)sin 0 0=?

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ezfong707 ezfong707 · Answer 1 · 2016-09-02T03:15:56+02:00

ezfong707 ezfong707

02-09-2016

Divide both sides by 1.5 to get.. 1.33sin(25°)/1.5 = sin(θ) Hence, by setting both sides by the inverse of sine... arcsin(sin(θ)) = arcsin(1.33sin(25°)/1.5) θ ≈ 22.01° I hope this helps!

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