Mariaeugeniaferminre
Mariaeugeniaferminre Mariaeugeniaferminre
  • 02-11-2020
  • Chemistry
contestada

11.Suppose you have the most abundant isotope of gold (Au). How many neutrons would it have? ​

Respuesta :

ardni313
ardni313 ardni313
  • 02-11-2020

Neutrons = 118

Further explanation  

The elements in nature have several types of isotopes  

Isotopes are elements that have the same Atomic Number (Proton)  

Atomic mass is the average atomic mass of all its isotopes  

The most abundant isotope of gold (Au) is isotope Au-197

So the atomic mass of Au = 197

and the atomic number of Au = 79

Atomic mass is the sum of protons and neutrons

Atomic Number (Z) = Atomic mass (A) - Neutrons

Neutrons = A - Z

So neutrons for Au-197 :

[tex]\tt neutrons=197-79=118[/tex]

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