parkevylin parkevylin

03-11-2020
Physics

contestada

a constant force acts on an object of mass 10 kg for a duration of 2 seconds it increases the object velocity from 4metre per sec to 8 metre per second find the magnitude of the applied force

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neemoneemo93 neemoneemo93

03-11-2020

Answer:

F=ma

a=v/t

a=vf-vi/t

a=8-4/2

a=4÷2

a=2msec*2

F=10×2

F=20N

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