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01-12-2020
Mathematics

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What is the standard form of –23f² + f/2 = –√3?

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01-12-2020

Answer:

y = -23f^2 + 1/2f + √3

Step-by-step explanation:

Standard form: y = ax^2 + bx + c

x = f

a = -23

b = 1/2

c = √3

–23f² + f/2 = -√3

-23f² + f/2 + √3 = 0

y = -23f^2 + f/2 + √3

y = -23f^2 + 1/2f + √3

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